7. You put a 45.8 gram mass on a spring, set it in motion with a small amplitude, and count 19 cycles. Those 19 cycles took 3.18 seconds. is k

7. You put a 45.8 gram mass on a spring, set it in motion with a small amplitude, and count 19 cycles. Those 19 cycles took 3.18 seconds. is k ? [removed] Nm . Answer with three significant figures or N/A if not enough information is given. 8. Use Hooke’s Law for this (F = – k s ): Where F is the spring’s restoring force; k is the spring constant; and s is the stretch. The negative sign means the spring’s restoring force is opposite the stretch direction. You have a plot from weight [N] versus stretch [m]. The data forms a linear trend y = 3.565 * x + 1.58. How much will the spring stretch if 45.8 grams is hung on the spring? [removed] [cm] Answer in centimeters with three significant figures or N/A if not enough information is given to answer. When you calculate your ansswer, don’t use the negative sign in the Hooke’s Law formula. Just know that the negative sign simply denotes the force direction is opposite the stretch (or compression).